improving obstacle detection with trigonometry

[Pierre-Marie Baty]

Heck, how does he manage to find all this stuff...

if I understand you right,

			   n  (2n+1)
		   (-1) .x
sin (x) ~= -------------
			  (2n+1)!

but what is n ?

[@$3.1415rin]

almost ... you take each n from 0 to infinity and sum up all those terms. so sin x is not what you said, but the sum of all those terms. now you can take only the first parts of the sum if you only need convergence around 0

but using a table would be the best solution in your case I guess