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Bert · *Last edited by Bert; 20-01-2004 at 21:40..*

You could solve this with the cosine rule (or whatever it's called in english (translating from dutch here)).

if you got the following situation:

then:

L2²=L1²+L3²-2*L1*L2*cos(a)

You can get cos(a) from that, so use arccos(L2²-etc. etc.) to get a.
[edit]

You could probably keep some sort of cosine table, so you can do rough estimates instead of calculating that arccos everytime

[/edit]

	(#4)
Bert Member Status: Offline Posts: 11 Join Date: Jan 2004	Re: The f____ shield. How to get bots to deal with it? - 20-01-2004 You could solve this with the cosine rule (or whatever it's called in english (translating from dutch here)). if you got the following situation: then: L2²=L1²+L3²-2L1L2cos(a) You can get cos(a) from that, so use arccos(L2²-etc. etc.) to get a. [edit] You could probably keep some sort of cosine table, so you can do rough estimates instead of calculating that arccos everytime [/edit] Last edited by Bert; 20-01-2004 at 21:40..*